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(C) Given: The number of waves in glass $(N_g)$ is equal to the number of waves in water $(N_w)$.$N_g = N_w$Since the number of waves $N = \frac{d}{\l

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$1.3$

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(C) Given: The number of waves in glass $(N_g)$ is equal to the number of waves in water $(N_w)$.$N_g = N_w$Since the number of waves $N = \frac{d}{\lambda}$,where $d$ is the thickness of the medium and $\lambda$ is the wavelength in that medium:$\frac{d_g}{\lambda_g} = \frac{d_w}{\lambda_w}$We know that $\lambda = \frac{\lambda_{	ext{air}}}{\mu}$,where $\mu$ is the refractive index.Substituting this into the equation:$\frac{d_g \cdot \mu_g}{\lambda_{	ext{air}}} = \frac{d_w \cdot \mu_w}{\lambda_{	ext{air}}}$$\mu_g \cdot d_g = \mu_w \cdot d_w$Given $d_g = 5 \ cm$,$d_w = 6 \ cm$,and $\mu_g = 1.56$:$1.56 	imes 5 = \mu_w 	imes 6$$\mu_w = \frac{1.56 	imes 5}{6} = \frac{7.8}{6} = 1.30$Thus,the refractive index of water is $1.30$.

When the same monochromatic ray of light travels through a glass slab and through water,the number of waves in a glass slab of thickness $5 \ cm$ is the same as in a water column of height $6 \ cm$. If the refractive index of glass is $1.56$,then the refractive index of water is:

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