(D) Given: $\lambda_1 = 0.26 \mu m$, $\lambda_2 = 0.13 \mu m$.According to Wien's displacement law, $\lambda T = \text{constant}$.Therefore, $\lambda_

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Given: $\lambda_1 = 0.26 \mu m$, $\lambda_2 = 0.13 \mu m$.According to Wien's displacement law, $\lambda T = \text{constant}$.Therefore, $\lambda_1 T_1 = \lambda_2 T_2$.$\frac{T_1}{T_2} = \frac{\lambda_2}{\lambda_1} = \frac{0.13}{0.26} = \frac{1}{2}$.According to Stefan-Boltzmann law, the emissive power $E \propto T^4$.Thus, the ratio of emissive powers is $\frac{E_1}{E_2} = \left(\frac{T_1}{T_2}\right)^4$.$\frac{E_1}{E_2} = \left(\frac{1}{2}\right)^4 = \frac{1}{16}$.So, the ratio is $1:16$.

Class 11 Physics 10-2.Heat Transfer Radiation by Stefan's Boltzmann Law

Difficult

When the temperature of a black body increases, it is observed that the wavelength corresponding to maximum energy changes from $0.26 \mu m$ to $0.13 \mu m$. The ratio of the emissive powers of the body at the respective temperatures is

TS EAMCET 2002 All TS EAMCET

AP EAMCET 2002 All AP EAMCET

A
$16:1$
B
$4:1$
C
$1:4$
D
$1:16$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

10-2.Heat Transfer

Subtopic

Radiation by Stefan's Boltzmann Law

Previous Year

TS EAMCET 2002 Paper All TS EAMCET years →

Previous Year

AP EAMCET 2002 Paper All AP EAMCET years →

For two identical cylindrical emitters,the ratio of their radii is $1:4$ and the ratio of their temperatures is $2:1$. The ratio of the amount of heat emitted by them is ....... (Assume length is proportional to radius for the cylinders).

Difficult

View Solution

Two identical bodies have temperatures $277^{\circ} C$ and $67^{\circ} C$. If the surroundings temperature is $27^{\circ} C$, the ratio of loss of heats of the two bodies during the same interval of time is (approximately) (in $ : 1$)

DifficultAP EAMCET 2005

View Solution

Two bodies $X$ and $Y$ at temperatures $T_1 \ K$ and $T_2 \ K$ respectively have the same dimensions. If their emissive powers are the same,the relation between their temperatures is:

EasyMHT CET 2024

View Solution

The operating temperature and emissivity of a tungsten filament are $2000 \ K$ and $0.3$,respectively. The surface area of the filament is $A \ cm^2$. If the power of the lamp is $25 \ W$,find $A$. (Given: $\sigma = 5.67 \times 10^{-8} \ W/m^2K^4$)

Medium

View Solution

If the temperature of a black body is increased from $27^{\circ}C$ to $327^{\circ}C$,the radiation emitted increases by a factor of:

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

When the temperature of a black body increases, it is observed that the wavelength corresponding to maximum energy changes from $0.26 \mu m$ to $0.13 \mu m$. The ratio of the emissive powers of the body at the respective temperatures is

Similar Questions

For two identical cylindrical emitters,the ratio of their radii is $1:4$ and the ratio of their temperatures is $2:1$. The ratio of the amount of heat emitted by them is ....... (Assume length is proportional to radius for the cylinders).

Two identical bodies have temperatures $277^{\circ} C$ and $67^{\circ} C$. If the surroundings temperature is $27^{\circ} C$, the ratio of loss of heats of the two bodies during the same interval of time is (approximately) (in $ : 1$)

Two bodies $X$ and $Y$ at temperatures $T_1 \ K$ and $T_2 \ K$ respectively have the same dimensions. If their emissive powers are the same,the relation between their temperatures is:

The operating temperature and emissivity of a tungsten filament are $2000 \ K$ and $0.3$,respectively. The surface area of the filament is $A \ cm^2$. If the power of the lamp is $25 \ W$,find $A$. (Given: $\sigma = 5.67 \times 10^{-8} \ W/m^2K^4$)

If the temperature of a black body is increased from $27^{\circ}C$ to $327^{\circ}C$,the radiation emitted increases by a factor of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module