When yellow light is incident on a surface,no | vedclass

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(A) The energy of a photon is given by $E = \frac{hc}{\lambda}$.According to the photoelectric effect,emission occurs only if the incident light frequ

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No electrons are emitted

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(A) The energy of a photon is given by $E = \frac{hc}{\lambda}$.According to the photoelectric effect,emission occurs only if the incident light frequency is greater than the threshold frequency,or the wavelength is less than the threshold wavelength $(\lambda Given that green light causes emission but yellow light does not,the threshold wavelength $\lambda_0$ must lie between the wavelengths of green and yellow light $(\lambda_g Since the wavelength of red light is greater than that of yellow light $(\lambda_r > \lambda_y)$,it follows that $\lambda_r > \lambda_0$.Because the wavelength of red light is greater than the threshold wavelength,the energy of red light photons is insufficient to overcome the work function of the surface.Therefore,no electrons are emitted when red light is incident on the surface.

When yellow light is incident on a surface,no electrons are emitted,while green light can emit them. If red light is incident on the surface,then:

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