Which carbon atom of glucose, numbered from 1 | vedclass

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(D) $1$. In the open-chain structure of glucose, the aldehyde group is at $C-1$.$2$. The hydroxyl $(-OH)$ group at $C-5$ attacks the carbonyl carbon $

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$C-5$

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(D) $1$. In the open-chain structure of glucose, the aldehyde group is at $C-1$.$2$. The hydroxyl $(-OH)$ group at $C-5$ attacks the carbonyl carbon $(C-1)$ to form a stable six-membered pyranose ring.$3$. This intramolecular reaction between the aldehyde group at $C-1$ and the hydroxyl group at $C-5$ results in the formation of a hemiacetal structure.$4$. Therefore, the $C-5$ carbon atom is involved in the ring closure.

Which carbon atom of glucose, numbered from $1$ to $6$, forms a hemiacetal structure by reacting with the $-CHO$ group to close the ring?

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