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The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:

The allowed set of quantum numbers for an electron in a hydrogen atom is

Nitrogen has the electronic configuration $1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1$ and not $1s^2 2s^2 2p_x^2 2p_y^1 2p_z^0$,which is determined by:

Identify the pair of orbitals having similar $(n + l)$ values from the following.

Following Hund's rule,which element contains six unpaired electrons?

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