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(C) Given that the object is moving with a constant negative acceleration,we have $a = -C$,where $C$ is a positive constant.Using the kinematic relati

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(C) Given that the object is moving with a constant negative acceleration,we have $a = -C$,where $C$ is a positive constant.Using the kinematic relation $a = v \frac{dv}{dx}$,we get:$v \frac{dv}{dx} = -C$$v \, dv = -C \, dx$Integrating both sides,we get:$\int v \, dv = \int -C \, dx$$\frac{v^2}{2} = -Cx + k$$v^2 = -2Cx + 2k$This equation represents a parabola of the form $v^2 = -Ax + B$,which corresponds to a velocity-distance graph that is concave downward,starting from a positive velocity and decreasing to zero as distance increases. This matches the graph in option $C$.

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?

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