Which intermediate is formed in the Reimer-Ti | vedclass

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(D) In the Reimer-Tiemann reaction,phenol is treated with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$.This reaction pro

Vedclass · Accepted Answer

Substituted benzal chloride

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(D) In the Reimer-Tiemann reaction,phenol is treated with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$.This reaction proceeds via the formation of a dichlorocarbene $(:CCl_2)$ intermediate,which attacks the phenoxide ion to form a substituted benzal chloride intermediate.This intermediate is subsequently hydrolyzed to form salicylaldehyde.Therefore,the intermediate formed is a substituted benzal chloride.

Which intermediate is formed in the Reimer-Tiemann reaction?

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