Which of the following statements is correct | vedclass

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(C) Let us analyze each option:$A$: $I$ $IP$ of $He$ $(1s^2)$ is $2372 \ kJ/mol$. $II$ $IP$ of $Li$ $(1s^2 2s^1 \rightarrow 1s^2)$ is $7298 \ kJ/mol$.

Vedclass · Accepted Answer

$III$ $IP$ of $Al$ is more than $III$ $IP$ of $Mg$

Vedclass · Answer

(C) Let us analyze each option:$A$: $I$ $IP$ of $He$ $(1s^2)$ is $2372 \ kJ/mol$. $II$ $IP$ of $Li$ $(1s^2 2s^1 \rightarrow 1s^2)$ is $7298 \ kJ/mol$. Thus,$II$ $IP$ of $Li > I$ $IP$ of $He$. Option $A$ is incorrect.$B$: $II$ $IP$ of $Mg$ $([Ne] 3s^2 \rightarrow [Ne] 3s^1)$ involves removing an electron from a stable $3s^1$ configuration. $II$ $IP$ of $Na$ $([Ne] 3s^1 \rightarrow [Ne])$ involves removing an electron from a stable noble gas configuration $([Ne])$. Therefore,$II$ $IP$ of $Na > II$ $IP$ of $Mg$. Option $B$ is incorrect.$C$: $III$ $IP$ of $Al$ $([Ne] 3s^2 3p^1 \rightarrow [Ne] 3s^2)$ involves removing an electron from a stable $3s^2$ configuration. $III$ $IP$ of $Mg$ $([Ne] 3s^2 \rightarrow [Ne] 3s^1)$ involves removing an electron from a stable $3s^2$ configuration,but $Mg$ has a lower nuclear charge than $Al$. Comparing the energy required,$III$ $IP$ of $Al$ is indeed higher than $III$ $IP$ of $Mg$ because $Al$ has a higher effective nuclear charge. Option $C$ is correct.

Which of the following statements is correct regarding the ionization potential $(IP)$?

Similar Questions

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