Which is the correct decreasing order of boil | vedclass

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(D) $1$. Boiling point depends on the molecular mass and the magnitude of van der Waals forces (dipole-dipole and London dispersion forces).$2$. As th

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$CHBr_3 > CH_2Br_2 > CH_3Br > CH_3Cl$

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(D) $1$. Boiling point depends on the molecular mass and the magnitude of van der Waals forces (dipole-dipole and London dispersion forces).$2$. As the number of bromine atoms increases in the haloalkane, the molecular mass increases significantly.$3$. Higher molecular mass leads to stronger van der Waals forces, resulting in a higher boiling point.$4$. Comparing the compounds: $CHBr_3$ (tribromomethane) has the highest molecular mass, followed by $CH_2Br_2$ (dibromomethane), then $CH_3Br$ (bromomethane), and finally $CH_3Cl$ (chloromethane) which has the lowest molecular mass.$5$. Therefore, the decreasing order is $CHBr_3 > CH_2Br_2 > CH_3Br > CH_3Cl$.

Which is the correct decreasing order of boiling points for the following compounds?

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