Which is the correct order of ionic sizes $(At. \, No. : Ce = 58, Sn = 50, Yb = 70, Lu = 71)$?

  • A
    $Sn^{4+} > Ce^{4+} > Yb^{3+} > Lu^{3+}$
  • B
    $Ce^{4+} > Sn^{4+} > Yb^{3+} > Lu^{3+}$
  • C
    $Lu^{3+} > Yb^{3+} > Sn^{4+} > Ce^{4+}$
  • D
    $Sn^{4+} > Yb^{3+} > Ce^{4+} > Lu^{3+}$

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What are the formulae of the compounds formed when lanthanoids $(Ln)$ react with nitrogen and halogen respectively?

Match the properties given in List-$I$ with the elements given in List-$II$:
List-$I$ (Property) List-$II$ (Element)
$(A)$ Lanthanoid showing $+4$ oxidation state $(i)$ $Pm$
$(B)$ Lanthanoid showing $+2$ oxidation state $(ii)$ $Ce$
$(C)$ Radioactive lanthanoid $(iii)$ $Lu$
$(D)$ Lanthanoid with $4f^7$ configuration in $+3$ state $(iv)$ $Eu$
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- $(vi)$ $Dy$

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