Which of the following electronic configurati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Molecular Orbital Theory $(MOT)$,for homonuclear and heteronuclear diatomic molecules with $14$ or fewer electrons,the order of energ

Vedclass · Accepted Answer

$CO : \sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^2$

Vedclass · Answer

(A) According to Molecular Orbital Theory $(MOT)$,for homonuclear and heteronuclear diatomic molecules with $14$ or fewer electrons,the order of energy is $\sigma 1s For molecules with more than $14$ electrons,the order is $\sigma 1s $CO$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^2$.$CN^-$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^2$.$NO$ ($15$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2pz^2, \pi 2px^2, \pi 2py^2, \pi^* 2px^1$.$N_2^+$ ($13$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2px^2, \pi 2py^2, \sigma 2pz^1$.All given options represent correct configurations based on the $MOT$ energy order.

Which of the following electronic configurations is correct for the given species?

Similar Questions

Provide the electron configuration,magnetic property,bond order,and energy level diagram for the carbon molecule $(C_2)$.

The bond order in $N_2^+$ ion is

The number of antibonding electron pairs in $O_2^{2-}$ molecular ion on the basis of molecular orbital theory is

Select the incorrect statement.

The calculated bond order of superoxide ion $(O_{2}^{-})$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module