Which of the following acids does NOT undergo | vedclass

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(D) The $Hell-Volhard-Zelinsky$ $(HVZ)$ reaction occurs in carboxylic acids that contain at least one $\alpha-hydrogen$ atom. In this reaction,the $\a

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Methanoic acid

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(D) The $Hell-Volhard-Zelinsky$ $(HVZ)$ reaction occurs in carboxylic acids that contain at least one $\alpha-hydrogen$ atom. In this reaction,the $\alpha-hydrogen$ is replaced by a halogen (chlorine or bromine) in the presence of red phosphorus. $Butanoic$ $acid$ $(CH_3CH_2CH_2COOH)$,$Propanoic$ $acid$ $(CH_3CH_2COOH)$,and $Ethanoic$ $acid$ $(CH_3COOH)$ all possess $\alpha-hydrogen$ atoms and thus undergo the $HVZ$ reaction. $Methanoic$ $acid$ $(HCOOH)$,also known as $Formic$ $acid$,does not contain an $\alpha-carbon$ atom,and consequently,it lacks an $\alpha-hydrogen$ atom. Therefore,$Methanoic$ $acid$ does not undergo the $HVZ$ reaction.

Which of the following acids does $NOT$ undergo the Hell-Volhard-Zelinsky reaction?

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