Which of the following alkenes will yield 2-m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Reductive ozonolysis of an alkene involves breaking the $C=C$ double bond and replacing it with two $C=O$ bonds.For $2-$methyl propanal $(CH_3-CH(

Vedclass · Accepted Answer

$2,5-$dimethylhex$-3-$ene

Vedclass · Answer

(C) Reductive ozonolysis of an alkene involves breaking the $C=C$ double bond and replacing it with two $C=O$ bonds.For $2-$methyl propanal $(CH_3-CH(CH_3)-CHO)$,the structure is a $4-$carbon chain with a methyl group on the $2^{nd}$ carbon and an aldehyde group on the $1^{st}$ carbon.If we take $2,5-$dimethylhex$-3-$ene,the structure is $(CH_3)_2CH-CH=CH-CH(CH_3)_2$.Upon reductive ozonolysis,the double bond breaks to form two molecules of $2-$methyl propanal,$(CH_3)_2CH-CHO$.Thus,the correct option is $(C)$.

Which of the following alkenes will yield $2-$methyl propanal on reductive ozonolysis (addition with ozone followed by the reaction with $Zn / H_2 O$)?

Similar Questions

Which of the following reactions does not involve a carbocation as an intermediate?

The major product of the reaction is:

$2-$chlorobutane is heated with alcoholic $NaOH$. The product formed in larger amount is:

Ozonolysis of an alkene produces only one dicarbonyl compound. The structure of the alkene is:

The general formula of alkenes is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module