Which of the following can show geometrical i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Geometrical isomerism requires restricted rotation (like a double bond or a ring) and different groups attached to each carbon atom involved in th

Vedclass · Accepted Answer

$1-$ethyl$-2-$methylcyclobutane

Vedclass · Answer

(C) Geometrical isomerism requires restricted rotation (like a double bond or a ring) and different groups attached to each carbon atom involved in the restricted rotation.$A$: $2,3$-dimethylbut-$2$-ene is $(CH_3)_2C=C(CH_3)_2$. Both carbons of the double bond have identical methyl groups,so it cannot show geometrical isomerism.$B$: $1$-methylcyclohex-$1$-ene has the double bond within a six-membered ring. The carbons at positions $1$ and $2$ are part of the ring,and the geometry is fixed,preventing cis-trans isomerism in such a small ring.$C$: $1$-ethyl-$2$-methylcyclobutane has a cyclic structure. The substituents at positions $1$ and $2$ can be on the same side (cis) or opposite sides (trans) of the ring plane,thus it shows geometrical isomerism.$D$: $CH_3-C \equiv C-CH_2CH_3$ contains a triple bond,which is linear and cannot show geometrical isomerism.

Which of the following can show geometrical isomerism?

Similar Questions

According to the $E$ and $Z$ nomenclature,which isomer is $E$?

How many geometrical isomers are possible for the compound $1,3,5$-trimethylcyclohexane?

The correct order of heat of combustion for the following alkadienes is:

Which one of the following is a diastereomer of $(R)-4$-bromo-cis-$2$-hexene?

In the following structure,the double bonds are marked as $I$,$II$,$III$ and $IV$. Geometrical isomerism is not possible at site$(s)$:

Vedclass Test Series

Exam Paper Generator

Online Exam Module