Which of the following can show hyperconjugat | vedclass

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Question

(B) Hyperconjugation in free radicals requires the presence of $\alpha$-hydrogen atoms (hydrogens attached to the carbon atom adjacent to the radical

Vedclass · Accepted Answer

$CH_3-C^\bullet(CH_3)-CH_3$

Vedclass · Answer

(B) Hyperconjugation in free radicals requires the presence of $\alpha$-hydrogen atoms (hydrogens attached to the carbon atom adjacent to the radical center).$1.$ In option $(a)$,$CH_3-C(CH_3)_2-C^\bullet H_2$,the carbon adjacent to the radical center is a quaternary carbon with no hydrogens ($0$ $\alpha$-$H$).$2.$ In option $(b)$,$CH_3-C^\bullet(CH_3)-CH_3$,there are three methyl groups attached to the radical center,providing a total of $9$ $\alpha$-hydrogens. Thus,it shows hyperconjugation.$3.$ In option $(c)$,$CH_2=CH-C^\bullet H_2$ (allyl radical) is stabilized primarily by resonance.$4.$ In option $(d)$,the benzyl radical is stabilized primarily by resonance with the benzene ring.

Which of the following can show hyperconjugation?

Similar Questions

Identify the atoms or groups from the following that exhibit $-R$ effect and $+R$ effect when present on a benzene ring:
$-OR, -NHCOR, -CN, -X, -NO_2, -NH_2, -CHO$

Polarization of electrons in acrolein may be written as

Given below are two statements:
Statement $I$: On the basis of inductive effect, the order of stability of alkyl carbanions is $CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$.
Statement $II$: Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.

The decreasing order of stability of the following anions is:
$(P)$ $p-OCH_3-C_6H_4-CH_2^-$
$(Q)$ $p-CHO-C_6H_4-CH_2^-$
$(R)$ $p-Cl-C_6H_4-CH_2^-$
$(S)$ $p-CH_3-C_6H_4-CH_2^-$

What is the inductive effect? Explain it in detail.

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