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(C) To determine the highest paramagnetic behaviour,we calculate the number of unpaired electrons $(n)$ in each complex:$A$) $[Zn(NH_3)_6]^{2+}$: $Zn^

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$[Cr(NH_3)_6]^{3+}$

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(C) To determine the highest paramagnetic behaviour,we calculate the number of unpaired electrons $(n)$ in each complex:$A$) $[Zn(NH_3)_6]^{2+}$: $Zn^{2+}$ is $3d^{10}$. Unpaired electrons $(n)$ = $0$.$B$) $[Ti(NH_3)_6]^{3+}$: $Ti^{3+}$ is $3d^1$. Unpaired electrons $(n)$ = $1$.$C$) $[Cr(NH_3)_6]^{3+}$: $Cr^{3+}$ is $3d^3$. Unpaired electrons $(n)$ = $3$.$D$) $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. Unpaired electrons $(n)$ = $0$.Since $[Cr(NH_3)_6]^{3+}$ has the maximum number of unpaired electrons $(n=3)$,it exhibits the highest paramagnetic behaviour.

Which of the following complex compounds will exhibit highest paramagnetic behaviour? (At. No. $Ti = 22$,$Cr = 24$,$Co = 27$,$Zn = 30$)

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