Which of the following complexes is paramagne | vedclass

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Question

(D) $1$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$,outer orbital complex $(sp^3d^2)$,paramagnetic,coloured.$2$. $[Co(H_2O)_6]^{2+}$: $Co^{2+}$ is $3d^7

Vedclass · Accepted Answer

$[Co(NH_3)_6]^{3+}$

Vedclass · Answer

(D) $1$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$,outer orbital complex $(sp^3d^2)$,paramagnetic,coloured.$2$. $[Co(H_2O)_6]^{2+}$: $Co^{2+}$ is $3d^7$,outer orbital complex $(sp^3d^2)$,paramagnetic,coloured.$3$. $[Ti(H_2O)_6]^{3+}$: $Ti^{3+}$ is $3d^1$,outer orbital complex $(sp^3d^2)$,paramagnetic,coloured.$4$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. It forms an inner orbital complex $(d^2sp^3)$. Since it has no unpaired electrons,it is diamagnetic and colourless.Wait,re-evaluating the question criteria: Paramagnetic,inner orbital,and coloured. None of the options perfectly fit all three criteria simultaneously based on standard ligand field theory. However,if we consider $[Co(NH_3)_6]^{3+}$ as the target for inner orbital,it is diamagnetic. Given the options,there might be a typo in the question. If we look for paramagnetic and coloured,$A, B, C$ are candidates. If we look for inner orbital,only $D$ is a candidate. Assuming the question implies a complex like $[Fe(CN)_6]^{3-}$,but among these,$[Co(NH_3)_6]^{3+}$ is the only inner orbital complex.

Which of the following complexes is paramagnetic,an inner orbital complex,and coloured?

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