Which of the following complexes does not sho | vedclass

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(C) Geometrical isomerism is shown by complexes that have different spatial arrangements of ligands around the central metal ion.For octahedral comple

Vedclass · Accepted Answer

$[Cr(OX)_3]^{3-}$

Vedclass · Answer

(C) Geometrical isomerism is shown by complexes that have different spatial arrangements of ligands around the central metal ion.For octahedral complexes of the type $[MA_6]$,$[MA_5B]$,$[MA_4B_2]$,$[MA_3B_3]$,and $[MA_2B_4]$,geometrical isomerism is possible.Option $A$: $[Co(NH_3)_4Cl_2]^+$ is of the type $[MA_4B_2]$,which shows $cis$ and $trans$ isomers.Option $B$: $[Fe(NH_3)_2(CN)_4]^-$ is of the type $[MA_2B_4]$,which shows $cis$ and $trans$ isomers.Option $C$: $[Cr(OX)_3]^{3-}$ contains a bidentate ligand $(OX^{2-})$. Complexes of the type $[M(AA)_3]$ do not show geometrical isomerism because all positions are equivalent.Option $D$: $[Co(NH_3)_3(NO_2)_3]$ is of the type $[MA_3B_3]$,which shows facial $(fac)$ and meridional $(mer)$ isomers.Therefore,the correct answer is $C$.

Which of the following complexes does not show geometrical isomerism?

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