Find the value of spin-only magnetic moment f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The atomic number of $Zn$ is $30$. The electronic configuration of $Zn$ is $[Ar] 3d^{10} 4s^2$. The electronic configuration of $Zn^{2+}$ is $[Ar]

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(C) The atomic number of $Zn$ is $30$. The electronic configuration of $Zn$ is $[Ar] 3d^{10} 4s^2$. The electronic configuration of $Zn^{2+}$ is $[Ar] 3d^{10}$. Since all $10$ electrons in the $3d$ subshell are paired,the number of unpaired electrons $(n)$ is $0$. The formula for spin-only magnetic moment is $\mu = \sqrt{n(n+2)} \ BM$. Substituting $n = 0$,we get $\mu = \sqrt{0(0+2)} = 0 \ BM$.

Find the value of spin-only magnetic moment for $Zn^{2+}$ in $BM$.

Similar Questions

Complexes $[Co(NH_3)_5SO_4]Br$ and $[Co(NH_3)_5Br]SO_4$ can be distinguished by

Which one of the following complexes will most likely absorb visible light? (At. nos. $Sc = 21$,$Ti = 22$,$V = 23$,$Zn = 30$)

The total number of isomers for the square planar complex $K_2[PdClBr_2(SCN)]$ is/are:

Which of the following complexes is capable of showing optical isomerism?

What is the spin-only magnetic moment (in Bohr Magneton units) of $Ni^{2+}$ in an aqueous solution? (Atomic number of $Ni = 28$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module