Which of the following compounds is planar an | vedclass

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(C) To determine if a molecule is planar and non-polar,we analyze its geometry and dipole moment:$1$. $XeO_4$: It has a tetrahedral geometry ($sp^3$ h

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$XeF_4$

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(C) To determine if a molecule is planar and non-polar,we analyze its geometry and dipole moment:$1$. $XeO_4$: It has a tetrahedral geometry ($sp^3$ hybridization). It is non-polar but non-planar.$2$. $SF_4$: It has a see-saw geometry ($sp^3d$ hybridization) due to one lone pair. It is polar and non-planar.$3$. $XeF_4$: It has a square planar geometry ($sp^3d^2$ hybridization) with two lone pairs occupying axial positions. The dipole moments cancel out,making it non-polar and planar.$4$. $CF_4$: It has a tetrahedral geometry ($sp^3$ hybridization). It is non-polar but non-planar.Therefore,$XeF_4$ is both planar and non-polar.

Which of the following compounds is planar and non-polar?

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