Which of the following compounds undergo Cann | vedclass

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(C) Aldehydes that do not possess any $\alpha$-hydrogen atoms undergo the Cannizzaro reaction in the presence of a concentrated base. $(a)$ $HCHO$ (Fo

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$a, b, c$

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(C) Aldehydes that do not possess any $\alpha$-hydrogen atoms undergo the Cannizzaro reaction in the presence of a concentrated base. $(a)$ $HCHO$ (Formaldehyde): No $\alpha$-carbon,hence no $\alpha$-hydrogen. It undergoes Cannizzaro reaction. $(b)$ $C_6H_5-CHO$ (Benzaldehyde): The $\alpha$-carbon (the carbon attached to the aldehyde group) has no hydrogen atom attached to it. It undergoes Cannizzaro reaction. $(c)$ $CH_3-C(CH_3)_2-CHO$ ($2$,$2$-Dimethylpropanal): The $\alpha$-carbon is bonded to three methyl groups and has no $\alpha$-hydrogen. It undergoes Cannizzaro reaction. $(d)$ $Ph-CH_2-CHO$ (Phenylacetaldehyde): The $\alpha$-carbon is attached to two hydrogen atoms. It does not undergo Cannizzaro reaction. Therefore,compounds $(a)$,$(b)$,and $(c)$ undergo the Cannizzaro reaction.

Which of the following compounds undergo Cannizzaro reaction?
$(a)$ $HCHO$
$(b)$ $C_6H_5-CHO$
$(c)$ $CH_3-C(CH_3)_2-CHO$
$(d)$ $Ph-CH_2-CHO$

Similar Questions

In which of the following reactions is the product formed the same?

Consider the given reaction,the product $'X'$ is:

$CH_3CHO$ $\xrightarrow[5\,^{\circ}C]{10\%\,NaOH}$ $\xrightarrow[\Delta]{}$ $\xrightarrow[Ni]{H_2} (A)$; Product $(A)$ of the reaction is

Consider the following sequence of reactions:
Ketone $A$ $\xrightarrow[2. H_2O]{1. C_2H_5MgBr} B$ $\xrightarrow[- H_2O]{H_2SO_4, \text{Heat}} C$ $\xrightarrow[2. Zn, H_2O]{1. O_3} \text{Propanone} + \text{Acetaldehyde}$
The ketone $A$ is:

$CH_3CHO \xrightarrow{LiAlH_4} CH_3CH_2OH$
Which nucleophile is added in this reaction?

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Which of the following compounds undergo Cannizzaro reaction? $(a)$ $HCHO$ $(b)$ $C_6H_5-CHO$ $(c)$ $CH_3-C(CH_3)_2-CHO$ $(d)$ $Ph-CH_2-CHO$