Which of the following compounds can show geo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Geometrical isomerism requires restricted rotation (like a double bond or ring) and different groups on each carbon atom of the double bond or rin

Vedclass · Accepted Answer

$I$,$II$ and $IV$

Vedclass · Answer

(D) Geometrical isomerism requires restricted rotation (like a double bond or ring) and different groups on each carbon atom of the double bond or ring.$I$. $CH_3-CH=CH-CH_2-CH_3$: This is pent-$2$-ene. Both carbons of the double bond have different groups attached ($H$ and $CH_3$ on one; $H$ and $C_2H_5$ on the other). It shows geometrical isomerism.$II$. $1,2$-dimethylcyclohexane: The ring structure restricts rotation. The two methyl groups can be on the same side $(cis)$ or opposite sides $(trans)$ of the ring plane. It shows geometrical isomerism.$III$. $CH_3-N=CH_2$: The nitrogen atom has a lone pair and a methyl group,but the terminal carbon has two identical hydrogen atoms. It does not show geometrical isomerism.$IV$. $C_2H_5-CH=N-OH$: This is an oxime. The nitrogen atom has a lone pair and an $-OH$ group,and the carbon atom has a hydrogen and an ethyl group. It shows geometrical isomerism ($syn/anti$ isomers).Therefore,$I$,$II$,and $IV$ show geometrical isomerism.

Which of the following compounds can show geometrical isomerism:
$I$. $CH_3-CH=CH-CH_2-CH_3$
$II$. $1,2$-dimethylcyclohexane
$III$. $CH_3-N=CH_2$
$IV$. $C_2H_5-CH=N-OH$

Similar Questions

$2$-Butene exhibits geometrical isomerism due to:

Which one of the following compounds will not show geometrical isomerism?

Identify the $E$ and $Z$ configurations for the following structures.

The compound that exhibits geometrical isomerism is .......

Which of the following will show geometrical isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following compounds can show geometrical isomerism:$I$. $CH_3-CH=CH-CH_2-CH_3$$II$. $1,2$-dimethylcyclohexane$III$. $CH_3-N=CH_2$$IV$. $C_2H_5-CH=N-OH$