Which of the following compounds is not forme | vedclass

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(B) The iodoform reaction of acetone involves the sequential replacement of hydrogen atoms on the alpha-carbon by iodine atoms in the presence of a ba

Vedclass · Accepted Answer

$ICH_2COCH_2I$

Vedclass · Answer

(B) The iodoform reaction of acetone involves the sequential replacement of hydrogen atoms on the alpha-carbon by iodine atoms in the presence of a base $(OI^-)$.Step $1$: $CH_3COCH_3 + OI^- \rightarrow CH_3COCH_2I + OH^-$Step $2$: $CH_3COCH_2I + OI^- \rightarrow CH_3COCH_2I + OH^-$Step $3$: $CH_3COCH_2I + OI^- \rightarrow CH_3COCI_3 + OH^-$Step $4$: $CH_3COCI_3 + OH^- \rightarrow CH_3COO^- + CHI_3$Comparing these intermediates with the given options, $ICH_2COCH_2I$ is not formed during the reaction as the iodination occurs specifically on the methyl group that is adjacent to the carbonyl group.

Which of the following compounds is not formed in the iodoform reaction of acetone?

Similar Questions

The ratio $x / y$ on completion of the above reaction is $.........$.

In the following reactions,
$CH_3COCH_3 \xrightarrow[(ii) D_3O^+]{(i) NaBH_4} X$
$CH_3COCH_3 \xrightarrow[(ii) H_3O^+]{(i) NaBD_4} Y$
$X$ and $Y$ are

Arrange the following compounds in order of decreasing reactivity for nucleophilic addition reaction:
$(I)$ $CH_3COCH_2Cl$
$(II)$ $ClCH_2CHO$
$(III)$ $HCHO$
$(IV)$ $CH_3COCH_3$

Which of the following reagents is suitable for the preparation of the product in the above reaction?

The reaction of ethyl methyl ketone with $Cl_2$ / excess $OH^{-}$ gives the following major product:

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