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(C) Nucleophilic addition reactivity depends on the electrophilicity of the carbonyl carbon and steric hindrance.$1.$ Aldehydes are generally more rea

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$II > III > I > IV$

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(C) Nucleophilic addition reactivity depends on the electrophilicity of the carbonyl carbon and steric hindrance.$1.$ Aldehydes are generally more reactive than ketones due to less steric hindrance and fewer electron-donating groups.$2.$ Electron-withdrawing groups (like $Cl$) increase the positive charge on the carbonyl carbon via the $-I$ effect,thereby increasing reactivity.Comparing the given compounds:- $(II)$ $ClCH_2CHO$ is an aldehyde with an electron-withdrawing group,making it the most reactive.- $(III)$ $HCHO$ is the simplest aldehyde with minimal steric hindrance.- $(I)$ $CH_3COCH_2Cl$ is a ketone with an electron-withdrawing group.- $(IV)$ $CH_3COCH_3$ is a simple ketone with two electron-donating methyl groups.Therefore,the order of decreasing reactivity is: $II > III > I > IV$.

Test	$C$	$D$
Ceric ammonium nitrate Test	Positive	Positive
Lucas Test	Turbidity obtained after five minutes	Turbidity obtained immediately
Iodoform Test	Positive	Negative

Arrange the following compounds in order of decreasing reactivity for nucleophilic addition reaction:
$(I)$ $CH_3COCH_2Cl$
$(II)$ $ClCH_2CHO$
$(III)$ $HCHO$
$(IV)$ $CH_3COCH_3$

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Arrange the following compounds in order of decreasing reactivity for nucleophilic addition reaction:$(I)$ $CH_3COCH_2Cl$$(II)$ $ClCH_2CHO$$(III)$ $HCHO$$(IV)$ $CH_3COCH_3$