Which of the following diagrams or statements | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For $sp$ hybridization: The mixing of one $s$ and one $p$ orbital (e.g.,$p_y$) results in two $sp$ hybrid orbitals oriented along the axis of the

Vedclass · Accepted Answer

All of these

Vedclass · Answer

(D) For $sp$ hybridization: The mixing of one $s$ and one $p$ orbital (e.g.,$p_y$) results in two $sp$ hybrid orbitals oriented along the axis of the $p$ orbital used. Thus,$s + p_y 	o 2sp$ along the $y$-axis is correct.For $sp^2$ hybridization: The mixing of one $s$ and two $p$ orbitals (e.g.,$p_y$ and $p_z$) results in three $sp^2$ hybrid orbitals lying in the plane defined by those two $p$ orbitals (the $yz$ plane). Thus,$s + p_y + p_z 	o sp^2$ orbitals in the $yz$ plane is correct.For $sp^3d^2$ hybridization: The mixing of one $s$,three $p$,and two $d$ orbitals results in six $sp^3d^2$ hybrid orbitals,which are directed towards the corners of an octahedron. Thus,this statement is also correct.Since all statements are correct,the correct option is $D$.

Which of the following diagrams or statements is correct for the hybrid orbitals?

Similar Questions

If two different non-axial $d-$orbitals having $xz$ nodal plane form $\pi-$bond by overlapping each other,then the internuclear axis will be:

In the formation of a molecule by atoms,which forces operate?

Bond length of ethane $(I)$, ethene $(II)$, acetylene $(III)$ and benzene $(IV)$ follows the order

Identify the correct statements from the following.
$(I)$ $SnCl_2$ is ionic,but $SnCl_4$ is covalent in nature.
$(II)$ All linear diatomic molecules have zero dipole moment.
$(III)$ Both $NO$ and $O_2$ are paramagnetic.

Choose the incorrect order of bond length $-$

Vedclass Test Series

Exam Paper Generator

Online Exam Module