Which of the following expressions is correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a $CsCl$ crystal structure,$Cl^{-}$ ions are located at the corners of a simple cubic unit cell,and the $Cs^{+}$ ion is located at the body cen

Vedclass · Accepted Answer

$r_c + r_a = \frac{\sqrt{3} a}{2}$

Vedclass · Answer

(C) In a $CsCl$ crystal structure,$Cl^{-}$ ions are located at the corners of a simple cubic unit cell,and the $Cs^{+}$ ion is located at the body center.Along the body diagonal of the cube,the $Cs^{+}$ ion and the $Cl^{-}$ ions at the corners touch each other.The length of the body diagonal of a cube with edge length $a$ is given by $\sqrt{3} a$.Since the body diagonal passes through two $Cl^{-}$ ions (at corners) and one $Cs^{+}$ ion (at the center),the length of the body diagonal is equal to $2r_a + 2r_c = 2(r_c + r_a)$.Equating the two expressions: $2(r_c + r_a) = \sqrt{3} a$.Therefore,$r_c + r_a = \frac{\sqrt{3} a}{2}$.

Which of the following expressions is correct in case of a $CsCl$ unit cell (edge length,$a$)?

Similar Questions

If $a \neq p, b \neq q, c \neq r$ and $\left|\begin{array}{ccc}p & b & c \\ p+a & q+b & 2c \\ a & b & r\end{array}\right|=0$,then $\frac{p}{p-a}+\frac{q}{q-b}+\frac{r}{r-c}$ is equal to :

If the internal energy of an ideal gas decreases by the same amount as the work done by the system,the process is

For any integer $n \geq 2$,let $I_n = \int \tan^n x \, dx$. If $I_n = \frac{1}{a} \tan^{n-1} x - b I_{n-2}$ for $n \geq 2$,then the ordered pair $(a, b)$ equals to

Two coherent sources of intensity ratio $x^2$ interfere. In the interference pattern,which of the following relations is correct?

If $u = x y^2 \tan^{-1}\left(\frac{y}{x}\right)$, then $x \frac{\partial u}{\partial x} + y \frac{\partial u}{\partial y}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module