Which of the following facts about the complex $[Cr(NH_3)_6]Cl_3$ is wrong?
- AThe complex involves $d^2sp^3$ hybridisation and is octahedral in shape.
- BThe complex is paramagnetic.
- CThe complex is an outer orbital complex.
- DThe complex gives white precipitate with silver nitrate solution.
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Similar Questions
Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is
$LIST-I$ $LIST-II$ $P. dsp^2$ $1. [FeF_6]^{4-}$ $Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$ $R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$ $S. d^2sp^3$ $4. [FeCl_4]^{2-}$ $5. Ni(CO)_4$ $6. [Ni(CN)_4]^{2-}$
| $LIST-I$ | $LIST-II$ |
| $P. dsp^2$ | $1. [FeF_6]^{4-}$ |
| $Q. sp^3$ | $2. [Ti(H_2O)_3Cl_3]$ |
| $R. sp^3d^2$ | $3. [Cr(NH_3)_6]^{3+}$ |
| $S. d^2sp^3$ | $4. [FeCl_4]^{2-}$ |
| $5. Ni(CO)_4$ | |
| $6. [Ni(CN)_4]^{2-}$ |
MediumIIT 2018
View SolutionMatch the following:
List-$I$ (Hybridisation) List-$II$ (Compound/ion) $A. sp^3d$ $I. [PtCl_4]^{2-}$ $B. sp^3d^2$ $II. SF_6$ $C. dsp^2$ $III. BCl_3$ $D. dsp^3$ $IV. PCl_5$ $V. ClF_3$
The correct match is:
| List-$I$ (Hybridisation) | List-$II$ (Compound/ion) |
|---|---|
| $A. sp^3d$ | $I. [PtCl_4]^{2-}$ |
| $B. sp^3d^2$ | $II. SF_6$ |
| $C. dsp^2$ | $III. BCl_3$ |
| $D. dsp^3$ | $IV. PCl_5$ |
| $V. ClF_3$ |
The correct match is:
What is the shape of $Fe(CO)_5$?
MediumAIPMT 2000
View SolutionWhich of the following complexes has its hybridisation correctly matched?
Difficult
View SolutionWhich one of the following is square planar in structure and has diamagnetic property?
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