Which of the following order(s) is/are correc | vedclass

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(D) Thermal stability of alkaline earth metal sulfates increases down the group as the size of the cation increases,making the metal-oxygen bond stron

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$A, B, C$ and $D$

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(D) Thermal stability of alkaline earth metal sulfates increases down the group as the size of the cation increases,making the metal-oxygen bond stronger relative to the sulfate ion. Thus,$BeSO_4 $(B)$ Melting point of alkali metal halides decreases as the size of the cation increases (lattice energy decreases). Thus,$NaCl > KCl > RbCl > CsCl$ is correct.$(C)$ Solubility of alkali metal hydroxides increases down the group due to a decrease in lattice energy being more significant than the decrease in hydration energy. Thus,$LiOH $(D)$ Lattice energy is inversely proportional to the inter-ionic distance. As the size of the anion increases $(F^-  KCl > KBr > KI$ is correct.Therefore,all statements $(A), (B), (C),$ and $(D)$ are correct.

Column-$I$	Column-$II$
$(a)$ $NaOH$	$(p)$ Silvine
$(b)$ $Na_2CO_3$	$(q)$ As cooling agent in nuclear reactor
$(c)$ Liquid $Na$	$(r)$ Detergent soap
$(d)$ Potassium	$(s)$ In purification of Bauxite

Which of the following order$(s)$ is/are correct?
$(A)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$
$(B)$ Melting point: $NaCl > KCl > RbCl > CsCl$
$(C)$ Solubility: $LiOH < NaOH$
$(D)$ Lattice energy: $KF > KCl > KBr > KI$

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Match Column-$I$ with Column-$II$ :

Column-$I$ Column-$II$

$(a)$ $NaOH$ $(p)$ Silvine

$(b)$ $Na_2CO_3$ $(q)$ As cooling agent in nuclear reactor

$(c)$ Liquid $Na$ $(r)$ Detergent soap

$(d)$ Potassium $(s)$ In purification of Bauxite

Which of the following orders are correct?
$(I)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$
$(II)$ Basic nature: $ZnO > BeO > MgO > CaO$
$(III)$ Solubility in water: $LiOH > NaOH > KOH > RbOH$
$(IV)$ Melting point: $NaCl > KCl > RbCl > CsCl > LiCl$

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Which of the following order$(s)$ is/are correct?$(A)$ Thermal stability: $BeSO_4 < MgSO_4 < CaSO_4 < SrSO_4$$(B)$ Melting point: $NaCl > KCl > RbCl > CsCl$$(C)$ Solubility: $LiOH < NaOH$$(D)$ Lattice energy: $KF > KCl > KBr > KI$