Which of the following is most basic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the basicity,we look at the availability of the lone pair of electrons on the nitrogen atom for protonation.$A$. In Pyrrole,the lone

Vedclass · Accepted Answer

Piperidine

Vedclass · Answer

(D) To determine the basicity,we look at the availability of the lone pair of electrons on the nitrogen atom for protonation.$A$. In Pyrrole,the lone pair on the nitrogen atom is involved in the aromatic sextet,making it unavailable for protonation. Thus,it is very weakly basic.$B$. In Aniline,the lone pair on the nitrogen atom is in conjugation with the benzene ring,which reduces its availability for protonation.$C$. In Pyridine,the lone pair is in an $sp^2$ hybridized orbital. Although it is not involved in the aromatic system,the $sp^2$ character makes it less basic than aliphatic amines.$D$. In Piperidine,the nitrogen atom is $sp^3$ hybridized and there is no resonance or aromaticity to delocalize the lone pair. Therefore,the lone pair is highly available for protonation,making Piperidine the most basic among the given options.

Similar Questions

Consider the following compounds:
$I. CH_3-CH_2-NH_2$
$II. Ph-CH_2-NH_2$
$III. Ph-NH_2$
The correct order of their basic strength is:

Which of the following is the correct order for basic strength?

Which of the following is the correct increasing order of basic strength of the given compounds in aqueous solution?

Which of the following sets of reagents convert aniline to chlorobenzene?

Which among the following decreasing order of boiling points is correct for amines?

Vedclass Test Series

Exam Paper Generator

Online Exam Module