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Which of the following is the correct set of $4$ quantum numbers for the $19^{th}$ electron in Chromium (Atomic number = $24$) in accordance with the Aufbau principle?
- A$n=3, l=2, m=+2, s=+\frac{1}{2}$
- B$n=3, l=2, m=-2, s=+\frac{1}{2}$
- C$n=4, l=1, m=0, s=+\frac{1}{2}$
- D$n=4, l=0, m=0, s=+\frac{1}{2}$
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