Which of the following is the strongest base?

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Question

(D) In aniline,$N$-methylaniline,and o-toluidine,the lone pair of electrons on the nitrogen atom is in conjugation with the benzene ring,which decreas

Vedclass · Accepted Answer

Benzylamine $(C_6H_5CH_2NH_2)$

Vedclass · Answer

(D) In aniline,$N$-methylaniline,and o-toluidine,the lone pair of electrons on the nitrogen atom is in conjugation with the benzene ring,which decreases its availability for protonation,making them weaker bases.In benzylamine $(C_6H_5CH_2NH_2)$,the lone pair on the nitrogen atom is not in conjugation with the benzene ring because of the presence of a $-CH_2-$ group between the benzene ring and the nitrogen atom.Therefore,the lone pair is more available for protonation,making benzylamine the strongest base among the given compounds.

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