Which of the following is the strongest base?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the basicity,we look at the availability of the lone pair of electrons on the nitrogen atom:$1$. In $Piperidine$,the nitrogen is $sp^

Vedclass · Accepted Answer

Piperidine

Vedclass · Answer

(A) To determine the basicity,we look at the availability of the lone pair of electrons on the nitrogen atom:$1$. In $Piperidine$,the nitrogen is $sp^3$ hybridized and the lone pair is localized,making it the most basic.$2$. In $Pyridine$,the nitrogen is $sp^2$ hybridized,and the lone pair is in an $sp^2$ orbital,which is less basic than $sp^3$.$3$. In $Pyrrole$,the lone pair on nitrogen is involved in the aromatic sextet,making it unavailable for protonation,thus it is very weakly basic.$4$. In $Aniline$,the lone pair is delocalized into the benzene ring due to resonance,reducing its availability for protonation.Therefore,$Piperidine$ is the strongest base.

Similar Questions

In the following reaction,the product $(A)$ is:

In which of the following reactions is an alcohol formed as the major product?

$C_6H_5CONHCH_3$ can be converted into $C_6H_5CH_2NHCH_3$ by

Consider the following reaction sequence. The final product $D$ will be:
$C_6H_5CH_3$ $\xrightarrow[\Delta]{KMnO_4/H^+} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow[\Delta]{NH_3} C$ $\xrightarrow{KOH/Br_2} D$

The product of the mustard oil reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module