Which of the following lanthanoid ions is dia | vedclass

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(B) lanthanoid ion with no unpaired electrons is diamagnetic in nature.$Ce_{58} = [Xe] 4f^{2} 5d^{0} 6s^{2} \implies Ce^{2+} = [Xe] 4f^{2}$ (two unpai

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$Yb^{2+}$

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(B) lanthanoid ion with no unpaired electrons is diamagnetic in nature.$Ce_{58} = [Xe] 4f^{2} 5d^{0} 6s^{2} \implies Ce^{2+} = [Xe] 4f^{2}$ (two unpaired electrons)$Sm_{62} = [Xe] 4f^{6} 5d^{0} 6s^{2} \implies Sm^{2+} = [Xe] 4f^{6}$ (six unpaired electrons)$Eu_{63} = [Xe] 4f^{7} 5d^{0} 6s^{2} \implies Eu^{2+} = [Xe] 4f^{7}$ (seven unpaired electrons)$Yb_{70} = [Xe] 4f^{14} 5d^{0} 6s^{2} \implies Yb^{2+} = [Xe] 4f^{14}$ (no unpaired electrons)Because of the absence of unpaired electrons,$Yb^{2+}$ is diamagnetic.

Which of the following lanthanoid ions is diamagnetic?
(At. nos. $Ce = 58, Sm = 62, Eu = 63, Yb = 70$)

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Which of the following lanthanoid ions is diamagnetic?(At. nos. $Ce = 58, Sm = 62, Eu = 63, Yb = 70$)