Which of the following molecules/species is t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the stability of the given species,we apply $H$ückel's rule for aromaticity:$1$. $A$: The cyclopropenyl cation has $2 \pi$ electrons

Vedclass · Accepted Answer

Cyclopropenyl cation

Vedclass · Answer

(A) To determine the stability of the given species,we apply $H$ückel's rule for aromaticity:$1$. $A$: The cyclopropenyl cation has $2 \pi$ electrons ($n=0$,$4n+2=2$),is planar,and cyclic. It is aromatic and highly stable.$2$. $B$: The cyclopentadienyl cation has $4 \pi$ electrons $(4n=4)$,which makes it anti-aromatic and unstable.$3$. $C$: The cyclopropenyl anion has $4 \pi$ electrons $(4n=4)$,which makes it anti-aromatic and unstable.$4$. $D$: $1,3$-Cyclohexadiene is a non-aromatic conjugated diene,which is less stable than an aromatic system.Therefore,the cyclopropenyl cation is the most stable species due to its aromatic character.

Which of the following molecules/species is the most stable?

Similar Questions

In which of the following compounds,the $C-Cl$ bond ionisation shall give the most stable carbonium ion?

The order of stability of the following carbocations is:
$I$. $CH_2 = CH - CH_2^+$
$II$. $CH_3 - CH_2 - CH_2^+$
$III$. $C_6H_5CH_2^+$

Which of the following is not expected to be an intermediate of the following reaction?

Which of the following carbocations is the most stable?

Consider the following compound $(X)$:
$H-C \equiv C-CH_2-CH(CH_3)-CH_3$
The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module