Which of the following molecules has one lone pair of electrons on the central atom?

According to the $VSEPR$ theory,what is the shape of the water molecule $(H_2O)$?

Identify the number of molecules in which the central atom has one lone pair of electrons from the following list:
$PbCl_2, PH_3, ClF_3, SF_4, BF_3, SnCl_2$

Bond angle in $PH_{4}^{+}$ is more than that of $PH_{3}$. This is because

Consider the following information $(X = F$ or $Cl)$:

Molecule	$P-X$ (axial) bond length / $P-X$ (equatorial) bond length
$PF_5$	$a / b$
$PF_4CH_3$	$c / d$
$PF_3(CH_3)_2$	$e / f$
$PCl_5$	$g / h$

According to the given information,choose the incorrect order of bond lengths.

In the reaction given below,what are the geometries of $BCl_3$ and $X$ respectively?
$BCl_3 + NH_3 \rightarrow X$