Which of the following orders is correct?

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Question

(C) For $(a)$,the ionic size of isoelectronic species increases as the nuclear charge decreases: $Ca^{2+} (20) < K^{+} (19) < S^{2-} (16) < P^{3-} (15

Vedclass · Accepted Answer

$Al_{(aq.)}^{3+} > Mg_{(aq.)}^{2+} > Na_{(aq.)}^{+}$: Hydrated size

Vedclass · Answer

(C) For $(a)$,the ionic size of isoelectronic species increases as the nuclear charge decreases: $Ca^{2+} (20) For $(b)$,in aqueous solution,the extent of hydration decreases as the size of the cation increases $(Na^{+} > K^{+} > Rb^{+} > Cs^{+})$. Smaller hydrated ions move faster,but electrical conductance depends on the mobility of the hydrated ion. The order of ionic mobility and conductance in aqueous solution is $Cs^{+} > Rb^{+} > K^{+} > Na^{+}$. Thus,the given order is incorrect.For $(c)$,the extent of hydration is directly proportional to the charge density. $Al^{3+}$ has the highest charge density,followed by $Mg^{2+}$ and $Na^{+}$. Therefore,the hydrated size order is $Al_{(aq.)}^{3+} > Mg_{(aq.)}^{2+} > Na_{(aq.)}^{+}$. This is correct.For $(d)$,the extent of hydration for anions is $F^{-} > Cl^{-} > Br^{-} > I^{-}$. Consequently,the hydrated size is $F^{-} > Cl^{-} > Br^{-} > I^{-}$. Ionic mobility is inversely proportional to hydrated size,so the order is $I_{(aq.)}^{-} > Br_{(aq.)}^{-} > Cl_{(aq.)}^{-} > F_{(aq.)}^{-}$. Thus,the given order is incorrect.

Similar Questions

Arrange $Na, Na^+, F, F^-$ in the decreasing order of their radii (size).

If four different elements $A, B, C$ and $D$ have electronic configurations as $A = [Ne] 3s^2 3p^4$,$B = [Ne] 3s^2 3p^5$,$C = [Ar] 3d^{10} 4s^2 4p^4$ and $D = [Ar] 3d^{10} 4s^2 4p^5$,identify the element with the largest atomic radius.

Which of the following ions has the maximum ionic radius?

Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
The correct answer is:

What are the covalent and van der Waals radii in $Cl_2$?

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