Which of the following orders are correct aga | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $(I)$ Incorrect: In $NH_3$,the orbital dipole due to the lone pair and the net dipole moment of the three $N-H$ bonds are in the same direction,wh

Vedclass · Accepted Answer

$II, III$ only

Vedclass · Answer

(B) $(I)$ Incorrect: In $NH_3$,the orbital dipole due to the lone pair and the net dipole moment of the three $N-H$ bonds are in the same direction,whereas in $NF_3$,they are in opposite directions. Thus,$\mu(NH_3) > \mu(NF_3)$. $BF_3$ is symmetrical and has zero dipole moment. The correct order is $NH_3 > NF_3 > BF_3$.$(II)$ Correct: Bond length increases with the increase in the size of the atoms. Atomic radii follow the order $C > N > O > H$,so the bond length order $C-O > N-O > O-H$ is correct.$(III)$ Correct: According to Molecular Orbital Theory,the bond order of $C_2$ is $2$,$B_2$ is $1$,and $He_2$ is $0$. The order $C_2 > B_2 > He_2$ is correct.

Which of the following orders are correct against the property given?
$(I)$ Dipole moment $NF_3 > NH_3 > BF_3$
$(II)$ Covalent bond length $C-O > N-O > O-H$
$(III)$ Bond order $C_2 > B_2 > He_2$

Similar Questions

Identify a molecule with an incomplete octet from the following.

Which of the following is $INCORRECT$ regarding the molecule and the type of overlapping in the bridge bond?

Which one of the following bonds has the highest average bond energy $(kcal/mol)$?

If in $NH_3$ formation $N$ uses its pure atomic orbitals,then the wrong statement is:

The shapes of $BCl_3, PCl_3$ and $ICl_3$ molecules are all

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$(I)$	Dipole moment	$NF_3 > NH_3 > BF_3$
$(II)$	Covalent bond length	$C-O > N-O > O-H$
$(III)$	Bond order	$C_2 > B_2 > He_2$

Which of the following orders are correct against the property given? $(I)$Dipole moment$NF_3 > NH_3 > BF_3$$(II)$Covalent bond length$C-O > N-O > O-H$$(III)$Bond order$C_2 > B_2 > He_2$