Which of the following products is not formed | vedclass

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(B) The reaction of $Vinylcyclopentane$ with $HBr$ proceeds via the formation of a carbocation intermediate.$1$. Protonation of the double bond leads

Vedclass · Accepted Answer

$1-$Bromo$-2-$cyclopentyl-ethane

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(B) The reaction of $Vinylcyclopentane$ with $HBr$ proceeds via the formation of a carbocation intermediate.$1$. Protonation of the double bond leads to the formation of a secondary carbocation at the $\alpha$-position relative to the cyclopentyl ring.$2$. This secondary carbocation can undergo a ring expansion rearrangement to form a more stable tertiary carbocation (cyclohexyl cation).$3$. The secondary carbocation can also directly react with $Br^-$ to form $1-Bromo-1-cyclopentyl-ethane$ (Markovnikov product).$4$. The anti-Markovnikov product $1-Bromo-2-cyclopentyl-ethane$ is not formed under standard electrophilic addition conditions.$5$. The rearranged carbocation can react with $Br^-$ to form $Bromocyclohexane$ or $1-Bromo-1-methyl-cyclohexane$ depending on the specific rearrangement pathway.Therefore,$1-Bromo-2-cyclopentyl-ethane$ is not the expected product.

Which of the following products is not formed in the following reaction?
$Vinylcyclopentane + HBr \rightarrow ?$

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Which of the following products is not formed in the following reaction?$Vinylcyclopentane + HBr \rightarrow ?$