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(B) In option $B$,the starting material $(S)-3$-methylpent-$1$-ene contains a chiral center at $C-3$. When $HBr$ adds across the double bond via an el

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(B) In option $B$,the starting material $(S)-3$-methylpent-$1$-ene contains a chiral center at $C-3$. When $HBr$ adds across the double bond via an electrophilic addition mechanism,a new chiral center is formed at $C-2$. Since the original chiral center at $C-3$ remains unchanged,the addition of $Br^-$ can occur from either face of the carbocation intermediate,leading to two products that have the same configuration at $C-3$ but different configurations at $C-2$. These two products are diastereomers of each other.

Which of the following reactions results in the formation of a pair of diastereomers?

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In the given sequence of reactions,identify $P, Q, R$ and $S$ respectively.
$CH_2=CH_2 + Br_2$ $\xrightarrow{P} CH_2(Br)-CH_2(Br)$ $\xrightarrow{Q} CH_2=CH-Br$ $\xrightarrow{R} CH \equiv CH$ $\xrightarrow{S} C_6H_6$

Consider the following reaction sequence:
$C_6H_5CH=CH_2$ $\xrightarrow{Br_2} A$ $\xrightarrow{KMnO_4} B$
Compound $A$ and $B$ respectively are:

The major product of the reaction is:

Which of the following is not a member of the same homologous series?

The major product of the reaction is:

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Which of the following reactions results in the formation of a pair of diastereomers?

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In the given sequence of reactions,identify $P, Q, R$ and $S$ respectively.$CH_2=CH_2 + Br_2$ $\xrightarrow{P} CH_2(Br)-CH_2(Br)$ $\xrightarrow{Q} CH_2=CH-Br$ $\xrightarrow{R} CH \equiv CH$ $\xrightarrow{S} C_6H_6$

Consider the following reaction sequence:$C_6H_5CH=CH_2$ $\xrightarrow{Br_2} A$ $\xrightarrow{KMnO_4} B$Compound $A$ and $B$ respectively are:

The major product of the reaction is:

Which of the following is not a member of the same homologous series?

The major product of the reaction is:

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In the given sequence of reactions,identify $P, Q, R$ and $S$ respectively.
$CH_2=CH_2 + Br_2$ $\xrightarrow{P} CH_2(Br)-CH_2(Br)$ $\xrightarrow{Q} CH_2=CH-Br$ $\xrightarrow{R} CH \equiv CH$ $\xrightarrow{S} C_6H_6$

Consider the following reaction sequence:
$C_6H_5CH=CH_2$ $\xrightarrow{Br_2} A$ $\xrightarrow{KMnO_4} B$
Compound $A$ and $B$ respectively are: