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(D) The oxidising power of halogens in aqueous solution depends on the standard electrode potential $(E^{\circ})$,which is determined by the sum of en

Vedclass · Accepted Answer

$F_2 > Cl_2 > Br_2 > I_2$

Vedclass · Answer

(D) The oxidising power of halogens in aqueous solution depends on the standard electrode potential $(E^{\circ})$,which is determined by the sum of enthalpy changes: sublimation,dissociation,electron gain,and hydration enthalpy.For halogens,the reaction is: $X_{2(g/l/s)} + 2e^{-} \longrightarrow 2X^{-}_{(aq)}$.Due to the very high hydration enthalpy of the fluoride ion $(F^{-})$,the overall reduction process for $F_2$ is the most spontaneous.The hydration energy follows the order: $F^{-} > Cl^{-} > Br^{-} > I^{-}$.Consequently,the ease of reduction follows the order: $F_2 > Cl_2 > Br_2 > I_2$.Thus,the correct order of oxidising power is $F_2 > Cl_2 > Br_2 > I_2$.

Which of the following represents the correct order of oxidising power of halogens in water?

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