Which of the following shows only one monobro | vedclass

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Question

(B) The reaction of alkanes with $Br_2$ in the presence of light (free radical substitution) depends on the number of non-equivalent hydrogen atoms.$A

Vedclass · Accepted Answer

$2,2$-dimethylpropane

Vedclass · Answer

(B) The reaction of alkanes with $Br_2$ in the presence of light (free radical substitution) depends on the number of non-equivalent hydrogen atoms.$A$. But-$2$-ene: Contains different types of hydrogens (allylic and vinylic),leading to multiple products.$B$. $2,2$-dimethylpropane (neopentane): All $12$ hydrogen atoms are equivalent. Replacing any one of them with $Br$ results in the same product,$1$-bromo-$2,2$-dimethylpropane. Thus,it gives only one monobrominated product.$C$. But-$1$-yne: Contains different types of hydrogens,leading to multiple products.$D$. Butan-$2$-ol: Contains different types of hydrogens,leading to multiple products.Therefore,the correct answer is $B$.

Which of the following shows only one monobrominated compound upon reaction with $Br_2$ in the presence of light?

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