Which of the following species is not paramag | vedclass

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(B) To determine paramagnetism,we look for the presence of unpaired electrons using Molecular Orbital Theory $(MOT)$. $1$. $NO$ has $15$ electrons: $(

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$S^{2-}$

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(B) To determine paramagnetism,we look for the presence of unpaired electrons using Molecular Orbital Theory $(MOT)$. $1$. $NO$ has $15$ electrons: $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^1$. It has one unpaired electron,so it is paramagnetic. $2$. $S^{2-}$ has $18$ electrons $(16 + 2)$: $1s^2 2s^2 2p^6 3s^2 3p^6$. All electrons are paired,so it is diamagnetic. $3$. $O_2^-$ has $17$ electrons: $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2p_z)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\pi^* 2p_x)^2 (\pi^* 2p_y)^1$. It has one unpaired electron,so it is paramagnetic. $4$. $N_2^-$ has $15$ electrons: $(\sigma 1s)^2 (\sigma^* 1s)^2 (\sigma 2s)^2 (\sigma^* 2s)^2 (\pi 2p_x)^2 (\pi 2p_y)^2 (\sigma 2p_z)^2 (\pi^* 2p_x)^1$. It has one unpaired electron,so it is paramagnetic. Thus,$S^{2-}$ is the only species that is not paramagnetic (it is diamagnetic).

Which of the following species is not paramagnetic?

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