Which of the following species is the least s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The stability of a species is directly proportional to its bond order.Using Molecular Orbital Theory $(MOT)$,the bond orders are calculated as fol

Vedclass · Accepted Answer

$O_2^{2-}$

Vedclass · Answer

(B) The stability of a species is directly proportional to its bond order.Using Molecular Orbital Theory $(MOT)$,the bond orders are calculated as follows:$O_2^{+}$: Bond order = $(10 - 5) / 2 = 2.5$$O_2$: Bond order = $(10 - 6) / 2 = 2.0$$O_2^{-}$: Bond order = $(10 - 7) / 2 = 1.5$$O_2^{2-}$: Bond order = $(10 - 8) / 2 = 1.0$Since $O_2^{2-}$ has the lowest bond order of $1.0$,it is the least stable species among the given options.

Which of the following species is the least stable?

Similar Questions

The bond lengths of diatomic molecules of elements $X$,$Y$ and $Z$ respectively are $143 \text{ pm}$,$110 \text{ pm}$ and $121 \text{ pm}$. The atomic numbers of $X$,$Y$ and $Z$ respectively are:

In the process,$O_2^+ \to O_2^{2+} + e^-$,the electron lost is from:

Which of the following has the minimum bond length?

Of the species,$NO$,$NO^{+}$,$NO^{2+}$,$NO^{-}$,the one with minimum bond strength is:

Assertion : Fluorine molecule has bond order one.
Reason : The number of electrons in the antibonding molecular orbitals is two less than that in bonding molecular orbitals.

Vedclass Test Series

Exam Paper Generator

Online Exam Module