The bond lengths of diatomic molecules of ele | vedclass

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(A) We know that bond order is inversely proportional to bond length,i.e.,$	ext{Bond order} \propto \frac{1}{	ext{Bond Length}}$.As the bond order o

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$9, 7, 8$

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(A) We know that bond order is inversely proportional to bond length,i.e.,$	ext{Bond order} \propto \frac{1}{	ext{Bond Length}}$.As the bond order of a diatomic molecule increases,its bond length decreases.Based on the provided data:- For $X$: Bond length = $143 	ext{ pm}$,which corresponds to $F_2$ (Total electrons = $18$,Bond order = $1$),so atomic number = $9$.- For $Y$: Bond length = $110 	ext{ pm}$,which corresponds to $N_2$ (Total electrons = $14$,Bond order = $3$),so atomic number = $7$.- For $Z$: Bond length = $121 	ext{ pm}$,which corresponds to $O_2$ (Total electrons = $16$,Bond order = $2$),so atomic number = $8$.Thus,the atomic numbers of $X$,$Y$ and $Z$ are $9, 7, 8$ respectively.

The bond lengths of diatomic molecules of elements $X$,$Y$ and $Z$ respectively are $143 \text{ pm}$,$110 \text{ pm}$ and $121 \text{ pm}$. The atomic numbers of $X$,$Y$ and $Z$ respectively are:

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