Which of the following statements are correct | vedclass

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(B) $i$. In $[Mn(CN)_6]^{3-}$,$Mn^{3+}$ is $3d^4$. $CN^-$ is a strong field ligand,so it is $d^2sp^3$ (inner orbital) with $2$ unpaired electrons (par

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$i, iii$ only

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(B) $i$. In $[Mn(CN)_6]^{3-}$,$Mn^{3+}$ is $3d^4$. $CN^-$ is a strong field ligand,so it is $d^2sp^3$ (inner orbital) with $2$ unpaired electrons (paramagnetic). In $[MnCl_6]^{3-}$,$Mn^{3+}$ is $3d^4$. $Cl^-$ is a weak field ligand,so it is $sp^3d^2$ (outer orbital) with $4$ unpaired electrons (paramagnetic). Thus,$i$ is correct.$ii$. $[NiCl_4]^{2-}$ is $sp^3$ tetrahedral and paramagnetic ($2$ unpaired electrons). $[Ni(CO)_4]$ is $sp^3$ tetrahedral and diamagnetic. Thus,$ii$ is incorrect.$iii$. $[Co(NH_3)_6]^{3+}$ involves $d^2sp^3$ hybridization (inner orbital). $[Ni(NH_3)_6]^{2+}$ involves $sp^3d^2$ hybridization (outer orbital). Thus,$iii$ is correct.Therefore,the correct statements are $i$ and $iii$.

Which of the following statements are correct?
$i$. $[Mn(CN)_6]^{3-}, [MnCl_6]^{3-}$ both are paramagnetic
$ii$. Both $[NiCl_4]^{2-}, [Ni(CO)_4]$ are tetrahedral and diamagnetic
$iii$. $[Co(NH_3)_6]^{3+}$ is an inner orbital complex,but $[Ni(NH_3)_6]^{2+}$ is an outer orbital complex

Similar Questions

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Which of the following statements are correct?$i$. $[Mn(CN)_6]^{3-}, [MnCl_6]^{3-}$ both are paramagnetic$ii$. Both $[NiCl_4]^{2-}, [Ni(CO)_4]$ are tetrahedral and diamagnetic$iii$. $[Co(NH_3)_6]^{3+}$ is an inner orbital complex,but $[Ni(NH_3)_6]^{2+}$ is an outer orbital complex