Which of the following statements is correct | vedclass

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Question

(C) The kinetic energy $(KE)$ of photoelectrons is given by the equation: $KE = h
u - h
u_0$.When the incident frequency $
u > 
u_0$,then $KE > 0$

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The kinetic energy $(KE)$ of photoelectrons is given by the equation: $KE = h
u - h
u_0$.When the incident frequency $
u > 
u_0$,then $KE > 0$. Thus,statement $3$ is correct.Here,$
u$ is the frequency of incident light and $
u_0$ is the threshold frequency.Analyzing other statements:$1$. The number of photoelectrons ejected is directly proportional to the intensity of light,not inversely.$2$. When $
u $4$. When $
u = 
u_0$,$KE = 0$,meaning the electrons are just ejected but have no kinetic energy to move away from the surface.

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