Which of the following yields both alkane and | vedclass

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(A) The correct answer is $A$. $1$. Kolbe's electrolysis of concentrated aqueous solutions of sodium or potassium salts of saturated monocarboxylic ac

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Kolbe's reaction

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(A) The correct answer is $A$. $1$. Kolbe's electrolysis of concentrated aqueous solutions of sodium or potassium salts of saturated monocarboxylic acids yields higher alkanes at the anode. $2$. In the case of salts of dicarboxylic acids (e.g.,succinic acid salts),the electrolysis yields alkenes at the anode. $3$. Thus,depending on the starting material (monocarboxylic vs. dicarboxylic acid salts),Kolbe's reaction can yield both alkanes and alkenes. $4$. For monocarboxylic acid: $2CH_3COONa + 2H_2O \xrightarrow{	ext{electrolysis}} CH_3-CH_3 + 2CO_2 + H_2 + 2NaOH$. $5$. For dicarboxylic acid (e.g.,sodium succinate): $NaOOC-CH_2-CH_2-COONa + 2H_2O \xrightarrow{	ext{electrolysis}} CH_2=CH_2 + 2CO_2 + H_2 + 2NaOH$.

Which of the following yields both alkane and alkene?

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