Which one of the following compounds is optic | vedclass

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Question

(A) compound is optically active if it contains at least one chiral carbon atom (a carbon atom bonded to four different groups).$1$. $2-$Chloropentane

Vedclass · Accepted Answer

$2-$Chloropentane

Vedclass · Answer

(A) compound is optically active if it contains at least one chiral carbon atom (a carbon atom bonded to four different groups).$1$. $2-$Chloropentane: $CH_3-CHCl-CH_2-CH_2-CH_3$. The $C-2$ atom is bonded to $-H$,$-Cl$,$-CH_3$,and $-CH_2CH_2CH_3$. Since all four groups are different,it is a chiral center. Thus,it is optically active.$2$. $3-$Chloropentane: $CH_3-CH_2-CHCl-CH_2-CH_3$. The $C-3$ atom is bonded to two identical ethyl groups $(-CH_2CH_3)$,so it is achiral.$3$. $2-$Chloropropane: $CH_3-CHCl-CH_3$. The $C-2$ atom is bonded to two identical methyl groups $(-CH_3)$,so it is achiral.$4$. $2-$Chloro$-2-$methylbutane: $CH_3-CCl(CH_3)-CH_2-CH_3$. The $C-2$ atom is bonded to two identical methyl groups $(-CH_3)$,so it is achiral.Therefore,$2-$Chloropentane is the optically active compound.

Which one of the following compounds is optically active?

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