Which one of the following compounds will lib | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Compounds that are more acidic than $H_{2}CO_{3}$ (carbonic acid) will react with $NaHCO_{3}$ to liberate $CO_{2}$.$(CH_{3})_{3}NH^{+}Cl^{-}$ is a

Vedclass · Accepted Answer

$(CH_{3})_{3}NH^{+}Cl^{-}$

Vedclass · Answer

(B) Compounds that are more acidic than $H_{2}CO_{3}$ (carbonic acid) will react with $NaHCO_{3}$ to liberate $CO_{2}$.$(CH_{3})_{3}NH^{+}Cl^{-}$ is a salt of a weak base and a strong acid,making the cation $(CH_{3})_{3}NH^{+}$ acidic enough to react with $HCO_{3}^{-}$:$(CH_{3})_{3}NH^{+}Cl^{-} + NaHCO_{3} \longrightarrow (CH_{3})_{3}N + NaCl + H_{2}CO_{3}$$H_{2}CO_{3} \longrightarrow H_{2}O + CO_{2} \uparrow$Therefore,option $B$ is the correct answer.

Which one of the following compounds will liberate $CO_{2}$ when treated with $NaHCO_{3}$?

Similar Questions

The value of enthalpy of neutralization is the lowest for the reaction between:

What is the aqueous solution of $HCl$ known as?

An acid is a compound which furnishes ($Bronsted-Lowry$ concept):

What name is given to the reaction between hydrogen ion and hydroxyl ion?

Ammonium hydroxide $(NH_4OH)$ is a:

Vedclass Test Series

Exam Paper Generator

Online Exam Module