Which one of the following conversions involv | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let us analyze each conversion:$(a)$ $CH_{4}$ ($sp^{3}$,tetrahedral) $\longrightarrow C_{2}H_{6}$ ($sp^{3}$,tetrahedral). No change in hybridisati

Vedclass · Accepted Answer

$BF_{3} \longrightarrow BF_{4}^{-}$

Vedclass · Answer

(C) Let us analyze each conversion:$(a)$ $CH_{4}$ ($sp^{3}$,tetrahedral) $\longrightarrow C_{2}H_{6}$ ($sp^{3}$,tetrahedral). No change in hybridisation or shape.$(b)$ $NH_{3}$ ($sp^{3}$,trigonal pyramidal) $\longrightarrow NH_{4}^{+}$ ($sp^{3}$,tetrahedral). Change in shape,but no change in hybridisation.$(c)$ $BF_{3}$ ($sp^{2}$,trigonal planar) $\longrightarrow BF_{4}^{-}$ ($sp^{3}$,tetrahedral). Both hybridisation and shape change.$(d)$ $H_{2}O$ ($sp^{3}$,bent) $\longrightarrow H_{3}O^{+}$ ($sp^{3}$,trigonal pyramidal). Change in shape,but no change in hybridisation.Thus,the conversion of $BF_{3}$ into $BF_{4}^{-}$ involves a change in both hybridisation and shape.

Which one of the following conversions involves a change in both hybridisation and shape?

Similar Questions

Which of the following is an incorrect statement?

The total number of lone pairs of electrons in the given molecule is

Identify the statement$(s)$ which is(are) not correct from the following:
$a)$ $NH_3$ and $H_3O^+$ are isostructural
$b)$ $ClF_3$ has $T$-shape
$c)$ $O_2$ molecule is paramagnetic
$d)$ Bond order of $N_2^+$ is more than $N_2$

Observe the following molecules/ions: $NH_4^{+}, NH_3, BF_3, OH^{-}, CH_3^{+}, H^{+}, CO, C_2H_4$. The number of Lewis bases in the above list is:

Assertion: $H_2O$ and $XeF_4$ both have a plane of symmetry.
Reason: $H_2O$ is a polar molecule,whereas $XeF_4$ is a non-polar molecule.

Vedclass Test Series

Exam Paper Generator

Online Exam Module